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X^2-4X=91
We move all terms to the left:
X^2-4X-(91)=0
a = 1; b = -4; c = -91;
Δ = b2-4ac
Δ = -42-4·1·(-91)
Δ = 380
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{380}=\sqrt{4*95}=\sqrt{4}*\sqrt{95}=2\sqrt{95}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{95}}{2*1}=\frac{4-2\sqrt{95}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{95}}{2*1}=\frac{4+2\sqrt{95}}{2} $
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